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Assume that one of Squidward’s sons, who is heterozygous for the light blue body color, married a girl that was also heterozygous. Create a Punnett square to show the possibilities that would result if they had children.


A. List the possible genotypes and phenotypes for their children.

B. What are the chances of a child with light blue skin? ___%


C. What are the chances of a child with light green skin? ____%

1 answer

To create a Punnett square for this scenario, we first need to define the alleles. Let's assume that light blue body color (B) is dominant and light green body color (b) is recessive. Since both Squidward’s son and his wife are heterozygous for the light blue body color, their genotypes can be represented as Bb.

Punnett Square:

        B       b
      ----------------
   B |   BB   |   Bb   |
      ----------------
   b |   Bb   |   bb   |
      ----------------

A. Possible Genotypes and Phenotypes:

  1. Possible Genotypes:

    • BB (homozygous dominant)
    • Bb (heterozygous)
    • bb (homozygous recessive)

  2. Possible Phenotypes:

    • Light blue skin (BB or Bb)
    • Light green skin (bb)

B. Chances of a Child with Light Blue Skin:

To calculate the genotype for light blue skin:

  • BB (1 out of 4, or 25%)
  • Bb (2 out of 4, or 50%)

So, the total chance of a child having light blue skin is: \[ 25% (BB) + 50% (Bb) = 75% \]

Chances of a child with light blue skin: 75%

C. Chances of a Child with Light Green Skin:

The only genotype that leads to light green skin is bb:

  • bb (1 out of 4, or 25%)

Chances of a child with light green skin: 25%

Summary:

  • A. Possible genotypes: BB, Bb, bb; Possible phenotypes: Light blue skin, Light green skin.
  • B. Chances of a child with light blue skin: 75%
  • C. Chances of a child with light green skin: 25%