Question
Patrick met Patti at the dance. Both of them are heterozygous for their pink body color, which is dominant over a yellow body color. Create a Punnett square to show the possibilities that would result if Patrick and Patti had children. HINT: Read question #3!
A. List the possible genotypes and phenotypes for their children.
B. What are the percent chances of a child with a pink body?
C. What are the percent chances of a child with a yellow body?
A. List the possible genotypes and phenotypes for their children.
B. What are the percent chances of a child with a pink body?
C. What are the percent chances of a child with a yellow body?
Answers
GPT-4o mini
To solve this genetic cross, we need to establish a Punnett square for the offspring of Patrick and Patti, who are both heterozygous for the pink body color trait. In this case, we'll assign the alleles as follows:
- P = Pink body color (dominant)
- p = Yellow body color (recessive)
Since both Patrick and Patti are heterozygous, their genotypes are:
- Patrick: Pp
- Patti: Pp
### A. Punnett Square
Let's create the Punnett square:
```
P p
----------------
P | PP | Pp |
----------------
p | Pp | pp |
----------------
```
### Genotypes and Phenotypes
From the Punnett square, we can list the possible genotypes and phenotypes of their children:
1. **Genotypes:**
- PP (homozygous dominant)
- Pp (heterozygous)
- pp (homozygous recessive)
2. **Phenotypes:**
- Pink body: PP or Pp (both have at least one dominant P)
- Yellow body: pp (only recessive)
### B. Percent Chances of a Child with a Pink Body
To find the percent chances of a child with a pink body, we can look at the genotypes:
- There are 3 outcomes that result in a pink body (PP and Pp) out of 4 total outcomes.
So, the calculation is:
- Pink body = PP + Pp = 1 (PP) + 2 (Pp) = 3
- Total outcomes = 4
**Percent chance of pink body:**
\[
\frac{3}{4} \times 100 = 75\%
\]
### C. Percent Chances of a Child with a Yellow Body
The only genotype that results in a yellow body is pp.
- There is 1 outcome that results in a yellow body (pp) out of 4 total outcomes.
**Percent chance of yellow body:**
\[
\frac{1}{4} \times 100 = 25\%
\]
### Summary of Results
- A. Possible Genotypes: PP, Pp, pp; Possible Phenotypes: Pink, Yellow
- B. Percent chance of pink body: 75%
- C. Percent chance of yellow body: 25%
- P = Pink body color (dominant)
- p = Yellow body color (recessive)
Since both Patrick and Patti are heterozygous, their genotypes are:
- Patrick: Pp
- Patti: Pp
### A. Punnett Square
Let's create the Punnett square:
```
P p
----------------
P | PP | Pp |
----------------
p | Pp | pp |
----------------
```
### Genotypes and Phenotypes
From the Punnett square, we can list the possible genotypes and phenotypes of their children:
1. **Genotypes:**
- PP (homozygous dominant)
- Pp (heterozygous)
- pp (homozygous recessive)
2. **Phenotypes:**
- Pink body: PP or Pp (both have at least one dominant P)
- Yellow body: pp (only recessive)
### B. Percent Chances of a Child with a Pink Body
To find the percent chances of a child with a pink body, we can look at the genotypes:
- There are 3 outcomes that result in a pink body (PP and Pp) out of 4 total outcomes.
So, the calculation is:
- Pink body = PP + Pp = 1 (PP) + 2 (Pp) = 3
- Total outcomes = 4
**Percent chance of pink body:**
\[
\frac{3}{4} \times 100 = 75\%
\]
### C. Percent Chances of a Child with a Yellow Body
The only genotype that results in a yellow body is pp.
- There is 1 outcome that results in a yellow body (pp) out of 4 total outcomes.
**Percent chance of yellow body:**
\[
\frac{1}{4} \times 100 = 25\%
\]
### Summary of Results
- A. Possible Genotypes: PP, Pp, pp; Possible Phenotypes: Pink, Yellow
- B. Percent chance of pink body: 75%
- C. Percent chance of yellow body: 25%