Solve for all real values of x

3cos2x - 5cosx = 1

1 answer

Use cos2x = 2 cos^2x -1 and convert the equation to a second order polynomial in which cosx is the variable. There should be two possible values of cosx.
Similar Questions
  1. So I posted these...but no one answered them. Are they right?Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x. My
    1. answers icon 0 answers
  2. Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x.My answer: (pi/4)+2(pi)k, (7pi/4) + 2(pi)k Solve 2cos^2
    1. answers icon 0 answers
  3. Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x.My answer: (pi/4)+2(pi)k, (7pi/4) + 2(pi)k Solve 2cos^2
    1. answers icon 1 answer
  4. Compute inverse functions to four significant digits.cos^2x=3-5cosx rewrite it as.. cos^2x + 5cosx -3=0 now you have a
    1. answers icon 0 answers
more similar questions