Asked by Miranda
                Solve for all real values of x
3cos2x - 5cosx = 1
            
        3cos2x - 5cosx = 1
Answers
                    Answered by
            drwls
            
    Use cos2x = 2 cos^2x -1 and convert the equation to a second order polynomial in which cosx is the variable. There should be two possible values of cosx. 
    
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