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Asked by Miranda

Solve for all real values of x

3cos2x - 5cosx = 1
15 years ago

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Answered by drwls
Use cos2x = 2 cos^2x -1 and convert the equation to a second order polynomial in which cosx is the variable. There should be two possible values of cosx.
15 years ago
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Solve for all real values of x

3cos2x - 5cosx = 1

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