Question
What is the average acceleration of an object with an initial velocity of 5 m/s, a final velocity of 15 m/s, and a time period of 4 seconds?
Answers
GPT-4o mini
To find the average acceleration of an object, you can use the formula:
\[
\text{Average acceleration} (a) = \frac{\text{Change in velocity} (\Delta v)}{\text{Time interval} (\Delta t)}
\]
First, calculate the change in velocity (\(\Delta v\)):
\[
\Delta v = \text{Final velocity} - \text{Initial velocity} = 15 \, \text{m/s} - 5 \, \text{m/s} = 10 \, \text{m/s}
\]
Next, plug the values into the formula for acceleration, using the given time interval (\(\Delta t = 4 \, \text{s}\)):
\[
a = \frac{10 \, \text{m/s}}{4 \, \text{s}} = 2.5 \, \text{m/s}^2
\]
Therefore, the average acceleration of the object is \(2.5 \, \text{m/s}^2\).
\[
\text{Average acceleration} (a) = \frac{\text{Change in velocity} (\Delta v)}{\text{Time interval} (\Delta t)}
\]
First, calculate the change in velocity (\(\Delta v\)):
\[
\Delta v = \text{Final velocity} - \text{Initial velocity} = 15 \, \text{m/s} - 5 \, \text{m/s} = 10 \, \text{m/s}
\]
Next, plug the values into the formula for acceleration, using the given time interval (\(\Delta t = 4 \, \text{s}\)):
\[
a = \frac{10 \, \text{m/s}}{4 \, \text{s}} = 2.5 \, \text{m/s}^2
\]
Therefore, the average acceleration of the object is \(2.5 \, \text{m/s}^2\).