Question
car accelerates from 0 to 60 km/h in 10 seconds
Answers
GPT-4o mini
To analyze the acceleration of a car that goes from 0 to 60 km/h in 10 seconds, we can calculate the average acceleration.
1. **Convert the speed to meters per second (m/s)**:
\[
60 \text{ km/h} = \frac{60,000 \text{ meters}}{3,600 \text{ seconds}} = 16.67 \text{ m/s}
\]
2. **Calculate the average acceleration**:
Average acceleration (a) can be calculated using the formula:
\[
a = \frac{\Delta v}{\Delta t}
\]
where:
- \(\Delta v\) is the change in velocity (final velocity - initial velocity),
- \(\Delta t\) is the time taken for that change.
Here, the initial velocity (u) is 0 m/s, the final velocity (v) is 16.67 m/s, and the time (t) is 10 seconds.
\[
a = \frac{16.67 \text{ m/s} - 0 \text{ m/s}}{10 \text{ s}} = \frac{16.67 \text{ m/s}}{10 \text{ s}} = 1.667 \text{ m/s}^2
\]
Therefore, the average acceleration of the car is approximately \(1.67 \text{ m/s}^2\).
1. **Convert the speed to meters per second (m/s)**:
\[
60 \text{ km/h} = \frac{60,000 \text{ meters}}{3,600 \text{ seconds}} = 16.67 \text{ m/s}
\]
2. **Calculate the average acceleration**:
Average acceleration (a) can be calculated using the formula:
\[
a = \frac{\Delta v}{\Delta t}
\]
where:
- \(\Delta v\) is the change in velocity (final velocity - initial velocity),
- \(\Delta t\) is the time taken for that change.
Here, the initial velocity (u) is 0 m/s, the final velocity (v) is 16.67 m/s, and the time (t) is 10 seconds.
\[
a = \frac{16.67 \text{ m/s} - 0 \text{ m/s}}{10 \text{ s}} = \frac{16.67 \text{ m/s}}{10 \text{ s}} = 1.667 \text{ m/s}^2
\]
Therefore, the average acceleration of the car is approximately \(1.67 \text{ m/s}^2\).