To show that the Product Rule of Logarithms works for the base 4 expression \( \log_4 16 + \log_4 4 \), you should evaluate both logarithms and demonstrate that their sum equals \( \log_4 64 \).
Here is the reasoning:
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Calculate \( \log_4 16 \):
- Since \( 16 = 4^2 \), we have \( \log_4 16 = 2 \).
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Calculate \( \log_4 4 \):
- Since \( 4 = 4^1 \), we have \( \log_4 4 = 1 \).
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Now, sum the two results: \[ \log_4 16 + \log_4 4 = 2 + 1 = 3. \]
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Calculate \( \log_4 64 \):
- Since \( 64 = 4^3 \), we have \( \log_4 64 = 3 \).
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Compare the sums: \[ \log_4 16 + \log_4 4 = 3 = \log_4 64. \]
Thus, option "Evaluate both \( \log_4 16 \) and \( \log_4 4 \) and show that their sum is equal to the value of \( \log_4 64 \)" best describes how to show that the Product Rule of Logarithms works for this expression.