Question

What is the percentage increase in the water level of a swimming pool when it rises from 4.5 to 6 feet, rounded to the nearest tenth of a percent?

Answer 1

To find the percentage increase in the water level of the swimming pool, we can use the formula for percentage increase:

\[
\text{Percentage Increase} = \left( \frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \right) \times 100
\]

In this case, the old value is 4.5 feet and the new value is 6 feet. Plugging in these values:

\[
\text{Percentage Increase} = \left( \frac{6 - 4.5}{4.5} \right) \times 100
\]

Calculating the difference:

\[
6 - 4.5 = 1.5
\]

Now substitute back into the formula:

\[
\text{Percentage Increase} = \left( \frac{1.5}{4.5} \right) \times 100
\]

Now, we simplify \(\frac{1.5}{4.5}\):

\[
\frac{1.5}{4.5} = \frac{1.5 \div 1.5}{4.5 \div 1.5} = \frac{1}{3} \approx 0.3333
\]

Now multiply by 100:

\[
0.3333 \times 100 \approx 33.33
\]

Rounding to the nearest tenth of a percent:

\[
33.3\%
\]

Thus, the percentage increase in the water level of the swimming pool is approximately **33.3%**.