To solve the equation \( \ln(3) = \ln(12 - 12x) \), we can use the property that if \( \ln(a) = \ln(b) \), then \( a = b \). Therefore, we have:
\[ 3 = 12 - 12x \]
Next, we can solve for \( x \):
- Subtract 12 from both sides:
\[ 3 - 12 = -12x \]
\[ -9 = -12x \]
- Divide both sides by -12:
\[ x = \frac{-9}{-12} = \frac{9}{12} = \frac{3}{4} \]
Therefore, the solution to the equation \( \ln(3) = \ln(12 - 12x) \) is:
\[ x = \frac{3}{4} \]
None of the provided options seem to match \( x = \frac{3}{4} \). Please double-check your options. If you have more information or possible answers, let me know!