Which of the following equations is log9(−x−9)=−2

rewritten in exponential form?(1 point)
Responses

9⋅−2=−x−9
9 times negative 2 equals negative x minus 9

9−2=−x−9
9 superscript negative 2 baseline equals negative x minus 9

−29=−x−9
negative 2 superscript 9 baseline equals negative x minus 9

9−x−9=−2

1 answer

To rewrite the logarithmic equation \( \log_9(-x - 9) = -2 \) in exponential form, we use the definition of logarithms.

The general form is: \[ \log_b(a) = c \implies b^c = a \]

In this case:

  • \( b = 9 \)
  • \( c = -2 \)
  • \( a = -x - 9 \)

So the equation becomes: \[ 9^{-2} = -x - 9 \]

The correct choice is: \[ 9^{-2} = -x - 9 \]

Therefore, the correct response is: 9−2=−x−9.