Question

A one tonne moon obiter is to approach the moon and orbit through 270 degrees at an altitude of 100km. During this period its rockets are to be turned off. What is the required velocity of the obiter at the entry point to prevent the vehicle from crashing into the moon?

Answer 1

centripetal acceleation=gravitational acceleation

v^2/r= GMassmoon/r^2
where r is the radius of the moon+100km
solve for v

Answer 2

Thanks a lot