Solve the system of two equations using substitution.

y=2+3x
4x−3y=−16(1 point)
Responses

(2, 8)
left parenthesis 2 comma 8 right parenthesis

(−2, −4)
left parenthesis negative 2 comma negative 4 right parenthesis

(2, 10)
left parenthesis 2 comma 10 right parenthesis

(−2, 4)

1 answer

To solve the system of equations using substitution, we have the following equations:

  1. \( y = 2 + 3x \)
  2. \( 4x - 3y = -16 \)

We can substitute the expression for \( y \) from the first equation into the second equation.

Substituting \( y \):

\[ 4x - 3(2 + 3x) = -16 \]

Now, simplify the equation:

\[ 4x - 6 - 9x = -16 \]

Combine like terms:

\[ -5x - 6 = -16 \]

Add 6 to both sides:

\[ -5x = -16 + 6 \]

\[ -5x = -10 \]

Now, divide by -5:

\[ x = 2 \]

Now that we have \( x \), we can substitute it back into the first equation to find \( y \):

\[ y = 2 + 3(2) = 2 + 6 = 8 \]

So the solution to the system of equations is \( (2, 8) \).

Therefore, the correct response is:

(2, 8)