Question

Area of a tile shaped like a triangle with the base being 1 1/2 cm and the height being 2 1/2 cm

Answer 1

To find the area of a triangle, you can use the formula:

\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]

In this case, the base is \(1 \frac{1}{2}\) cm, which can be converted to an improper fraction:

\[
1 \frac{1}{2} = \frac{3}{2} \text{ cm}
\]

The height is \(2 \frac{1}{2}\) cm, which can also be converted:

\[
2 \frac{1}{2} = \frac{5}{2} \text{ cm}
\]

Now, plug the base and height values into the area formula:

\[
\text{Area} = \frac{1}{2} \times \frac{3}{2} \times \frac{5}{2}
\]

First, calculate the multiplication of the fractions:

\[
\text{Area} = \frac{1}{2} \times \frac{3 \times 5}{2 \times 2} = \frac{1}{2} \times \frac{15}{4} = \frac{15}{8}
\]

Now, you can convert \(\frac{15}{8}\) to a decimal or mixed number if necessary:

\[
\frac{15}{8} = 1 \frac{7}{8} \text{ cm}^2 = 1.875 \text{ cm}^2
\]

So the area of the triangular tile is \(\frac{15}{8}\) cm² or \(1.875\) cm².