Question

area of rectangle with a width of 6 1/2 centimeters and and length of 4 1/2 centimeters

Answer 1

To find the area of a rectangle, you multiply the width by the length.

First, let's convert the mixed numbers to improper fractions:

- The width \( 6 \frac{1}{2} \) can be converted as follows:
\[
6 \frac{1}{2} = 6 + \frac{1}{2} = \frac{12}{2} + \frac{1}{2} = \frac{13}{2}
\]

- The length \( 4 \frac{1}{2} \) can be converted as follows:
\[
4 \frac{1}{2} = 4 + \frac{1}{2} = \frac{8}{2} + \frac{1}{2} = \frac{9}{2}
\]

Now, multiply the two improper fractions to find the area:

\[
\text{Area} = \text{Width} \times \text{Length} = \left(\frac{13}{2}\right) \times \left(\frac{9}{2}\right) = \frac{13 \times 9}{2 \times 2} = \frac{117}{4} \text{ square centimeters}
\]

To convert \(\frac{117}{4}\) to a mixed number:
\[
117 \div 4 = 29 \quad \text{(with a remainder of 1)}
\]
Thus,
\[
\frac{117}{4} = 29 \frac{1}{4} \text{ square centimeters}
\]

So, the area of the rectangle is \( \frac{117}{4} \) square centimeters or \( 29 \frac{1}{4} \) square centimeters.