Question

give the chemical formula,molar mass,and % compostionn of the following problems.round to the nearest 10
Tetrabromine Octaflouride

Answer 1

To find the chemical formula, molar mass, and percent composition of Tetrabromine Octafluoride, we need to identify the components and their respective quantities in the compound.

1. **Chemical Formula**:
- "Tetrabromine" means there are four bromine (Br) atoms.
- "Octafluoride" means there are eight fluorine (F) atoms.
- Therefore, the chemical formula is: **Br₄F₈**.

2. **Molar Mass Calculation**:
- Atomic mass of Bromine (Br) ≈ 80 g/mol
- Atomic mass of Fluorine (F) ≈ 19 g/mol

Now we calculate the molar mass of Br₄F₈:
\[
\text{Molar mass of Br₄F₈} = (4 \times 80) + (8 \times 19)
\]
\[
= 320 + 152 = 472 \, \text{g/mol}
\]

3. **Percent Composition**:
To find the percent composition of each element in the compound:
- % Br:
\[
\% \text{Br} = \left( \frac{4 \times 80}{472} \right) \times 100 = \left( \frac{320}{472} \right) \times 100 \approx 68\% \text{ (rounded to the nearest 10)}
\]
- % F:
\[
\% \text{F} = \left( \frac{8 \times 19}{472} \right) \times 100 = \left( \frac{152}{472} \right) \times 100 \approx 32\% \text{ (rounded to the nearest 10)}
\]

So, the results are:
- **Chemical Formula**: Br₄F₈
- **Molar Mass**: 472 g/mol
- **Percent Composition**:
- % Br = 70%
- % F = 30%