Question
Which inequality is true when x = 8?
40x > 320
40x < 320
40x < -320
40x ≤ 320
40x > 320
40x < 320
40x < -320
40x ≤ 320
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To evaluate the inequalities for \( x = 8 \), we first calculate \( 40x \):
\[
40x = 40 \times 8 = 320
\]
Now, we can check each inequality with this result:
1. **For \( 40x > 320 \):**
\[
320 > 320 \quad (\text{False})
\]
2. **For \( 40x < 320 \):**
\[
320 < 320 \quad (\text{False})
\]
3. **For \( 40x < -320 \):**
\[
320 < -320 \quad (\text{False})
\]
4. **For \( 40x \leq 320 \):**
\[
320 \leq 320 \quad (\text{True})
\]
The only true inequality when \( x = 8 \) is:
\[
\boxed{40x \leq 320}
\]
\[
40x = 40 \times 8 = 320
\]
Now, we can check each inequality with this result:
1. **For \( 40x > 320 \):**
\[
320 > 320 \quad (\text{False})
\]
2. **For \( 40x < 320 \):**
\[
320 < 320 \quad (\text{False})
\]
3. **For \( 40x < -320 \):**
\[
320 < -320 \quad (\text{False})
\]
4. **For \( 40x \leq 320 \):**
\[
320 \leq 320 \quad (\text{True})
\]
The only true inequality when \( x = 8 \) is:
\[
\boxed{40x \leq 320}
\]
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