Asked by Teddy
(3^m)(5^(m+1))=12^(2m-1)
not sure how to solve this but I think you use natural logs? I'm just stuck because the first two are multiplying and not adding and we didn't go over this
not sure how to solve this but I think you use natural logs? I'm just stuck because the first two are multiplying and not adding and we didn't go over this
Answers
Answered by
Reiny
yes, take the log of both sides
log(3^m)(5^(m+1)) = log(12^(2m-1)
mlog3 + (m+1)log5 = (2m-1)log12
expand and you will get terms of m and constants, remember something like log12 is a constant
factor out m from the "m-terms" and solve for m
It is messy and long, be careful.
log(3^m)(5^(m+1)) = log(12^(2m-1)
mlog3 + (m+1)log5 = (2m-1)log12
expand and you will get terms of m and constants, remember something like log12 is a constant
factor out m from the "m-terms" and solve for m
It is messy and long, be careful.
Answered by
Teddy
I just solved for each log individually on my calculator and used decimals to find the answer, and it ended up being right
thanks!
thanks!
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