The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.

The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours.

How many times more was the electricity used in 1950 than 1902? Express your answer in Scientific Notation.

(1 point)
Responses

Multiply coefficients and add powers: 2.6×1021Multiply coefficients and add powers: 2.6×1021

Subtract coefficients and divide powers: 1.73×102Subtract coefficients and divide powers: 1.73×102

Add coefficients and add powers: 10.33×1020Add coefficients and add powers: 10.33×1020

Divide coefficients and subtract powers: 7.13×101Divide coefficients and subtract powers: 7.13×101

Divide coefficients and subtract powers: 1.4 x 102Divide coefficients and subtract powers: 1.4 x 102
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1 answer

To find how many times more electricity was used in 1950 than in 1902, we will divide the amount of electricity used in 1950 by the amount used in 1902.

  1. The amount used in 1902 is \(6.03 \times 10^9\) kilowatt-hours.
  2. The amount used in 1950 is \(4.3 \times 10^{11}\) kilowatt-hours.

Now perform the division:

\[ \frac{4.3 \times 10^{11}}{6.03 \times 10^9} \]

First, divide the coefficients:

\[ \frac{4.3}{6.03} \approx 0.712 \]

Next, subtract the exponents of 10:

\[ 10^{11 - 9} = 10^2 \]

Now, combine the results:

\[ 0.712 \times 10^2 \]

To express this in scientific notation, we need to adjust the coefficient to be between 1 and 10:

\[ 0.712 \times 10^2 = 7.12 \times 10^1 \]

So, the final answer is:

\[ \boxed{7.12 \times 10^1} \]

The closest response from the given options is "Divide coefficients and subtract powers: 7.13 × 10^1." This approximation is reasonable given the rounding in the coefficient calculation.