The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.

Question

The use of electricity in the US in 1950 was 4.3 x 10^11 kilowatt-hours.

What was the total kilowatt-hours of electricity used during these two years?

(1 point)
Responses

(6.03×109)×(4.3×1011)=25.929×102=2.6×101open paren 6 point 0 3 times 10 to the 9th power close paren times open paren 4 point 3 times 10 to the 11th power close paren is equal to 25 point 9 2 9 times 10 squared is equal to 2 point 6 times 10 to the 1th power

(6.03×109)×(4.3×1011)=25.929×1020=2.6×1019open paren 6 point 0 3 times 10 to the 9th power close paren times open paren 4 point 3 times 10 to the 11th power close paren is equal to 25 point 9 2 9 times 10 to the 20th power is equal to 2 point 6 times 10 to the 19th power

(6.03×109)+(4.3×1011)=10.33×1020=1.033×1019open paren 6 point 0 3 times 10 to the 9th power close paren plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 10 point 3 3 times 10 to the 20th power is equal to 1 point 0 3 3 times 10 to the 19th power

(6.03×109)+(4.3×1011)=0.063×1011+(4.3×1011)=4.3603×1011open paren 6 point 0 3 times 10 to the 9th power close paren plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 0 point 0 6 3 times 10 to the 11th power plus open paren 4 point 3 times 10 to the 11th power close paren is equal to 4 point 3 6 0 3 times 10 to the 11th power
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Answer 1

To find the total kilowatt-hours of electricity used during the years 1902 and 1950, we need to add the two values together.

The electricity usage in 1902 is: \[ 6.03 \times 10^9 \text{ kilowatt-hours} \]

The electricity usage in 1950 is: \[ 4.3 \times 10^{11} \text{ kilowatt-hours} \]

Since \( 4.3 \times 10^{11} \) is significantly larger than \( 6.03 \times 10^9 \), it's useful to rewrite the first value in terms of the same exponent for easier addition.

We can express \( 6.03 \times 10^9 \) as: \[ 0.0603 \times 10^{11} \]

Now we can add the two values: \[ 0.0603 \times 10^{11} + 4.3 \times 10^{11} = (0.0603 + 4.3) \times 10^{11} = 4.3603 \times 10^{11} \text{ kilowatt-hours} \]

Thus, the correct answer is: (6.03×10^9) + (4.3×10^11) = 4.3603×10^11