Triangle ABC

A
B
C
has vertices point A(2,1)
A
(
2
,
1
)
, point B(4,3)
B
(
4
,
3
)
, and point C(−2,5)
C
(

2
,
5
)
. Find the coordinates of A′
A

, B′
B

, and C′
C

after a dilation with a scale factor of 7 and a center point of dilation at the origin (0,0)
(
0
,
0
)
.

1 answer

To find the coordinates of the points \( A', B', \) and \( C' \) after a dilation with a scale factor of 7 and the center of dilation at the origin (0,0), we can apply the dilation formula:

\[ (x', y') = (kx, ky) \]

where \( (x, y) \) are the original coordinates of the point, \( (x', y') \) are the coordinates after dilation, and \( k \) is the scale factor.

Given the scale factor \( k = 7 \):

  1. For point \( A(2, 1) \):

\[ A' = (7 \cdot 2, 7 \cdot 1) = (14, 7) \]

  1. For point \( B(4, 3) \):

\[ B' = (7 \cdot 4, 7 \cdot 3) = (28, 21) \]

  1. For point \( C(-2, 5) \):

\[ C' = (7 \cdot -2, 7 \cdot 5) = (-14, 35) \]

Thus, the coordinates after dilation are:

  • \( A' = (14, 7) \)
  • \( B' = (28, 21) \)
  • \( C' = (-14, 35) \)