Asked by luna
Two vertices of a right triangle have the coordinates (−2, 5) and (9, 5) .
What is the length of the side formed by these vertices?
Enter your answer in the box.
units
What is the length of the side formed by these vertices?
Enter your answer in the box.
units
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the length of the side formed by the vertices \((-2, 5)\) and \((9, 5)\), we can calculate the distance between these two points. Since both points have the same y-coordinate, the distance is simply the difference in their x-coordinates.
The formula for the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
In this case:
- \(x_1 = -2\)
- \(y_1 = 5\)
- \(x_2 = 9\)
- \(y_2 = 5\)
Calculating the distance:
\[
d = \sqrt{(9 - (-2))^2 + (5 - 5)^2}
\]
\[
= \sqrt{(9 + 2)^2 + 0^2}
\]
\[
= \sqrt{11^2}
\]
\[
= \sqrt{121}
\]
\[
= 11
\]
Thus, the length of the side formed by these vertices is
\[
\boxed{11} \text{ units}
\]
The formula for the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
In this case:
- \(x_1 = -2\)
- \(y_1 = 5\)
- \(x_2 = 9\)
- \(y_2 = 5\)
Calculating the distance:
\[
d = \sqrt{(9 - (-2))^2 + (5 - 5)^2}
\]
\[
= \sqrt{(9 + 2)^2 + 0^2}
\]
\[
= \sqrt{11^2}
\]
\[
= \sqrt{121}
\]
\[
= 11
\]
Thus, the length of the side formed by these vertices is
\[
\boxed{11} \text{ units}
\]
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