Question
The smaller triangle was dilated to form the larger triangle. What is the value of x?
A smaller triangle has side lengths of 3 and 5. A larger triangle has side lengths of 9 and x + 1.
10
11
14
15
A smaller triangle has side lengths of 3 and 5. A larger triangle has side lengths of 9 and x + 1.
10
11
14
15
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve for \( x \), we can use the property of similar triangles that states the ratios of their corresponding sides are equal.
The side lengths of the smaller triangle are 3 and 5, and the larger triangle has side lengths of 9 and \( x + 1 \).
Let's use the side lengths 3 and 9 first. We set up the ratio:
\[
\frac{3}{9} = \frac{1}{3}
\]
Now we apply the same ratio to the other pair of corresponding sides:
\[
\frac{5}{x + 1}
\]
Setting the ratios equal, we have:
\[
\frac{5}{x + 1} = \frac{1}{3}
\]
Now we can cross-multiply to solve for \( x \):
\[
5 \cdot 3 = 1 \cdot (x + 1)
\]
This simplifies to:
\[
15 = x + 1
\]
Now subtract 1 from both sides:
\[
x = 15 - 1
\]
\[
x = 14
\]
Thus, the value of \( x \) is \( \boxed{14} \).
The side lengths of the smaller triangle are 3 and 5, and the larger triangle has side lengths of 9 and \( x + 1 \).
Let's use the side lengths 3 and 9 first. We set up the ratio:
\[
\frac{3}{9} = \frac{1}{3}
\]
Now we apply the same ratio to the other pair of corresponding sides:
\[
\frac{5}{x + 1}
\]
Setting the ratios equal, we have:
\[
\frac{5}{x + 1} = \frac{1}{3}
\]
Now we can cross-multiply to solve for \( x \):
\[
5 \cdot 3 = 1 \cdot (x + 1)
\]
This simplifies to:
\[
15 = x + 1
\]
Now subtract 1 from both sides:
\[
x = 15 - 1
\]
\[
x = 14
\]
Thus, the value of \( x \) is \( \boxed{14} \).
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