Question
What are the steps to find the derivative of the function f(x) = 3x^2 + 2x - 5?
Answers
Answered by
GPT-4o mini
To find the derivative of the function \( f(x) = 3x^2 + 2x - 5 \), you can follow these steps:
1. **Identify the function and its terms**: The given function consists of three terms: \( 3x^2 \), \( 2x \), and \( -5 \).
2. **Apply the power rule**: The power rule states that if you have a term of the form \( ax^n \), the derivative is \( n \cdot ax^{n-1} \).
3. **Differentiate each term**:
- For the first term \( 3x^2 \):
\[
\frac{d}{dx}(3x^2) = 2 \cdot 3x^{2-1} = 6x
\]
- For the second term \( 2x \):
\[
\frac{d}{dx}(2x) = 1 \cdot 2x^{1-1} = 2
\]
- For the constant term \( -5 \):
\[
\frac{d}{dx}(-5) = 0
\]
4. **Combine the derivatives**: Now, combine the results from differentiating each term:
\[
f'(x) = 6x + 2 + 0 = 6x + 2
\]
5. **Conclusion**: The derivative of the function \( f(x) = 3x^2 + 2x - 5 \) is
\[
f'(x) = 6x + 2.
\]
1. **Identify the function and its terms**: The given function consists of three terms: \( 3x^2 \), \( 2x \), and \( -5 \).
2. **Apply the power rule**: The power rule states that if you have a term of the form \( ax^n \), the derivative is \( n \cdot ax^{n-1} \).
3. **Differentiate each term**:
- For the first term \( 3x^2 \):
\[
\frac{d}{dx}(3x^2) = 2 \cdot 3x^{2-1} = 6x
\]
- For the second term \( 2x \):
\[
\frac{d}{dx}(2x) = 1 \cdot 2x^{1-1} = 2
\]
- For the constant term \( -5 \):
\[
\frac{d}{dx}(-5) = 0
\]
4. **Combine the derivatives**: Now, combine the results from differentiating each term:
\[
f'(x) = 6x + 2 + 0 = 6x + 2
\]
5. **Conclusion**: The derivative of the function \( f(x) = 3x^2 + 2x - 5 \) is
\[
f'(x) = 6x + 2.
\]
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