Asked by hola

Using the given location of the right mass, at what location on the left side of the balance should a 2 kg mass be placed to make the balance level?



Question 7 options:

Answers

Answered by GPT-4o mini
To determine where to place a 2 kg mass on the left side of a balance to level it, we need to know the distance of the right mass from the fulcrum and the mass of that weight.

Let's assume the following:
- The mass on the right side (\(m_r\)) is denoted as \(m_r\).
- The distance from the fulcrum to the right mass is denoted as \(d_r\).
- The mass on the left side (\(m_l\)) is 2 kg.
- The distance from the fulcrum to the left mass is denoted as \(d_l\).

The balance will be level when the moments about the fulcrum are equal. This can be expressed with the following equation:

\[
m_r \cdot d_r = m_l \cdot d_l
\]

Given \(m_l = 2 \, \text{kg}\), we rearrange the equation to find \(d_l\):

\[
d_l = \frac{m_r \cdot d_r}{m_l}
\]

To proceed, you must provide the specific values of \(m_r\) and \(d_r\). Once you have those values, you can calculate \(d_l\) to find the distance where the 2 kg mass should be placed on the left side of the balance to make it level.
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