To solve for \( y \) (the gallons of gas in the bus after 18 minutes), we will substitute \( x = 18 \) into the equation \( y = 10x + 35 \).
Starting with the equation:
\[ y = 10 \cdot 18 + 35 \]
Now, calculate \( 10 \cdot 18 \):
\[ 10 \cdot 18 = 180 \]
Now, add \( 35 \):
\[ y = 180 + 35 = 215 \]
Thus, the number of gallons of gas in the bus after 18 minutes will be:
\[ \boxed{215} \]
Summary of Key Points
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Points (4, 75) and (14, 175) represent the following:
- (4, 75): After 4 minutes, there are 75 gallons of gas in the bus.
- (14, 175): After 14 minutes, there are 175 gallons of gas in the bus.
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The equation representing the relationship between time and gallons of gas is:
\[ y = 10x + 35 \]
Where:
- \( m \) (the slope) is 10 (gallons of gas per minute).
- \( b \) (the y-intercept) is 35 (the initial amount of gas in the bus).