The table shows the results of rolling a number cube with sides labeled 1 through 6 several times.

Question

What is the experimental probability of rolling a 1 or a 5?

Enter your answer as a fraction in simplest form in the box.

$\text{Basic}$
$x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$
$x\frac{ }{ }$
$x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$
Outcome Number of times outcome occurred
1 10
2 6
3 4
4 8
5 6
6 6

Answer 1

To find the experimental probability of rolling a 1 or a 5, we first need to determine the total number of rolls and the number of times either outcome (1 or 5) occurred.

From the table provided:

• The outcome of rolling a 1 occurred 10 times.
• The outcome of rolling a 5 occurred 6 times.

Now, let's calculate the total occurrences of 1 or 5: \[ \text{Number of times 1 occurred} + \text{Number of times 5 occurred} = 10 + 6 = 16 \]

Next, we find the total number of rolls:

• This is the sum of all the outcomes recorded in the table: \[ 10 + 6 + 4 + 8 + 6 + 6 = 40 \]

Now, we can calculate the experimental probability of rolling a 1 or a 5: \[ P(\text{rolling a 1 or 5}) = \frac{\text{Number of times 1 or 5 occurred}}{\text{Total number of rolls}} = \frac{16}{40} \]

To simplify this fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 8: \[ \frac{16 \div 8}{40 \div 8} = \frac{2}{5} \]

Thus, the experimental probability of rolling a 1 or a 5 is: \[ \boxed{\frac{2}{5}} \]