Asked by peggy
find the product of (x^2-3x+5)with the quotient of (21x^6- 14x^5-7x^3)divide by 7x^3
Answers
Answered by
Reiny
I interpret your question as
(x^2-3x+5)(21x^6- 14x^5-7x^3)/(7x^3)
= (x^2-3x+5)(3x^3 - 2x^2 - 1)
expanding this gives you 6 different terms starting with 3x^5 and ending with -5
I would leave it in factored form.
Reply if my interpretation is incorrect, seems like very little happened.
btw, 3x^2 - 2x^2 - 1
factors to (x+1)(x-1)(3x+1)
but x^2 - 3x + 5 does not factor.
(x^2-3x+5)(21x^6- 14x^5-7x^3)/(7x^3)
= (x^2-3x+5)(3x^3 - 2x^2 - 1)
expanding this gives you 6 different terms starting with 3x^5 and ending with -5
I would leave it in factored form.
Reply if my interpretation is incorrect, seems like very little happened.
btw, 3x^2 - 2x^2 - 1
factors to (x+1)(x-1)(3x+1)
but x^2 - 3x + 5 does not factor.
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