Asked by Ziggy
Since I am new to the algebra and do not fully understand it, I am not sure how to answer the following question. Hope you can help. thanks
how do you know when an equation has infinitely many solutions
Answers
Answered by
Reiny
If after performing all valid steps, your variable terms all cancel and you end up with something like
0=0, or 8=8, that is, a <b>true</b> statement,
then you have an infinite number of solutions.
if after all variable terms drop out, you are left with a <b>false</b> statement, there is no solution.
e.g.
2x + 6 = 2(x+3+
2x +6 = 2x + 6+0=0 .....true ---> infinite number of solutions.
e.g
2x+6 = 2(x+5)
2x+6 = 2x+10
0 = 4 .... false ---> no solution
0=0, or 8=8, that is, a <b>true</b> statement,
then you have an infinite number of solutions.
if after all variable terms drop out, you are left with a <b>false</b> statement, there is no solution.
e.g.
2x + 6 = 2(x+3+
2x +6 = 2x + 6+0=0 .....true ---> infinite number of solutions.
e.g
2x+6 = 2(x+5)
2x+6 = 2x+10
0 = 4 .... false ---> no solution
Answered by
Reiny
clearly a typo, should be
2x + 6 = 2(x+3)
2x +6 = 2x + 6 .....true ---> infinite number of solutions.
2x + 6 = 2(x+3)
2x +6 = 2x + 6 .....true ---> infinite number of solutions.
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