A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)

Question

Responses

0.01 N
0.01 N

7.5 N
7.5 N

1 N
1 N

6.5 N

Answer 1

To find the force exerted on the tennis ball by the floor, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a):

\[ F = m \cdot a \]

In this case, we have:

• Mass of the tennis ball, \( m = 0.1 , \text{kg} \)
• Acceleration of the tennis ball, \( a = 10 , \text{m/s}^2 \)

Now we can calculate the force:

\[ F = 0.1 , \text{kg} \times 10 , \text{m/s}^2 = 1 , \text{N} \]

So the force exerted by the floor on the ball is 1 N.

Therefore, the correct response is:

1 N.