Let's solve each part one by one.
PART ONE: Solve for \( b \)
The equation is: \[ -20 = -5 + 3b \]
First, isolate \( 3b \): \[ -20 + 5 = 3b \] \[ -15 = 3b \]
Now, divide both sides by 3: \[ b = \frac{-15}{3} = -5 \]
Answer: \( b = -5 \)
PART TWO: Solve for \( x \)
The equation is: \[ 12x + 5 = 10x - 11 \]
First, isolate \( x \) by moving \( 10x \) to the left: \[ 12x - 10x + 5 = -11 \] \[ 2x + 5 = -11 \]
Now, move 5 to the right: \[ 2x = -11 - 5 \] \[ 2x = -16 \]
Now, divide both sides by 2: \[ x = \frac{-16}{2} = -8 \]
Answer: \( x = -8 \)
PART THREE: Solve for \( y \)
The equation is: \[ 4(y + 2) = 2(y + 6) \]
Distribute both sides: \[ 4y + 8 = 2y + 12 \]
Now, isolate \( y \) by moving \( 2y \) to the left: \[ 4y - 2y + 8 = 12 \] \[ 2y + 8 = 12 \]
Now, move 8 to the right: \[ 2y = 12 - 8 \] \[ 2y = 4 \]
Now, divide both sides by 2: \[ y = \frac{4}{2} = 2 \]
Answer: \( y = 2 \)
Summary of answers:
- \( b = -5 \)
- \( x = -8 \)
- \( y = 2 \)