Question

An Internet store charges a base fee of $5 plus $1.50 per pound to ship items. The table shows samples of their shipping rates. Fill in the missing values in the table.(3 points)
Weight of Package

(in pounds)

Shipping Cost

(in dollars)

2 8.00
5 12.50
7
15.50
9 18.50
10
20.00
17 30.50
Derek wants to ship items that weigh a total of 7 pounds, and Keisha wants to ship items that weigh a total of 10 pounds. Keisha spent
more than Derek.

Answers

GPT-4o mini
To find the missing values in the table, we can use the shipping cost formula based on the given information:

**Shipping Cost = Base Fee + (Cost per Pound × Weight)**

Here, the base fee is $5 and the cost per pound is $1.50.

We can calculate the shipping cost for each weight in the table:

1. **For 2 pounds:**
- Shipping Cost = $5 + ($1.50 × 2)
- Shipping Cost = $5 + $3.00 = $8.00 (This value is given)

2. **For 5 pounds:**
- Shipping Cost = $5 + ($1.50 × 5)
- Shipping Cost = $5 + $7.50 = $12.50 (This value is given)

3. **For 7 pounds:**
- Shipping Cost = $5 + ($1.50 × 7)
- Shipping Cost = $5 + $10.50 = $15.50

4. **For 9 pounds:**
- Shipping Cost = $5 + ($1.50 × 9)
- Shipping Cost = $5 + $13.50 = $18.50 (This value is given)

5. **For 10 pounds:**
- Shipping Cost = $5 + ($1.50 × 10)
- Shipping Cost = $5 + $15.00 = $20.00 (This value is given)

6. **For 17 pounds:**
- Shipping Cost = $5 + ($1.50 × 17)
- Shipping Cost = $5 + $25.50 = $30.50 (This value is given)

Now let's summarize the filled-in table:

| Weight of Package (in pounds) | Shipping Cost (in dollars) |
|--------------------------------|-----------------------------|
| 2 | 8.00 |
| 5 | 12.50 |
| 7 | 15.50 |
| 9 | 18.50 |
| 10 | 20.00 |
| 17 | 30.50 |

### Final Summary

- Derek wants to ship items that weigh a total of 7 pounds, and the shipping cost for that is **$15.50**.
- Keisha wants to ship items that weigh a total of 10 pounds, and the shipping cost for that is **$20.00**.
- Since **$20.00** (Keisha's cost) is greater than **$15.50** (Derek's cost), **Keisha spent more than Derek**.