Asked by izuku midoriya
A'(1, -3) B=(1, -1) C=(4, -3)
G=(-2,2) H=(-4, 2) E=(-2,5)
△ABC is congruent to △GHE . Describe a sequence of transformations from △ABC to △GHE that proves their congruence. (2 points)
G=(-2,2) H=(-4, 2) E=(-2,5)
△ABC is congruent to △GHE . Describe a sequence of transformations from △ABC to △GHE that proves their congruence. (2 points)
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Answered by
GPT-4o mini
To show that triangle \( \triangle ABC \) is congruent to triangle \( \triangle GHE \) through a sequence of transformations, we can describe the following steps:
1. **Translation**:
First, we need to translate \( \triangle ABC \) so that one of its vertices aligns with a vertex of \( \triangle GHE \).
We can translate point \( A' (1, -3) \) to point \( G (-2, 2) \). The translation vector can be calculated as:
\[
(-2 - 1, 2 - (-3)) = (-3, 5)
\]
Thus, we translate triangle \( ABC \) by the vector \( (-3, 5) \):
- \( A' \) moves to \( G \) at \( (-2, 2) \)
- \( B (1, -1) \) translates to \( (-2, 4) \)
- \( C (4, -3) \) translates to \( (1, 2) \)
After this translation, the points will be:
- \( A'' = G (-2, 2) \)
- \( B' = (-2, 4) \)
- \( C' = (1, 2) \)
2. **Rotation**:
Next, we need to perform a rotation or reflection so that the angles and order of the points match. To align \( B' \) and \( E (-2, 5) \), we look at the configuration of the points:
- Notice that \( B' (-2, 4) \) is directly below \( E (-2, 5) \), suggesting a potential rotation around point \( G (-2, 2) \).
To transform \( B' \) to \( E \) and align the remaining points correctly, we can rotate \( 90^\circ \) counter-clockwise around point \( G (-2, 2) \):
- The coordinates will transform as follows:
- Rotating \( A' (-2, 2) \) does not change (it stays \( G \)).
- Rotating \( B' (-2, 4) \) around \( G \) results in \( E (-2, 5) \).
- Rotating \( C' (1, 2) \) around \( G (-2, 2) \) results in the new position that aligns with \( H (-4, 2) \).
With these transformations, we show:
1. **Translation of \( \triangle ABC \)** such that point \( A' \) aligns with point \( G \).
2. **Rotation around \( G \)** to align all corresponding points.
Therefore, \( \triangle ABC \) can be transformed into \( \triangle GHE \) through the described sequence of transformations, proving their congruence.
1. **Translation**:
First, we need to translate \( \triangle ABC \) so that one of its vertices aligns with a vertex of \( \triangle GHE \).
We can translate point \( A' (1, -3) \) to point \( G (-2, 2) \). The translation vector can be calculated as:
\[
(-2 - 1, 2 - (-3)) = (-3, 5)
\]
Thus, we translate triangle \( ABC \) by the vector \( (-3, 5) \):
- \( A' \) moves to \( G \) at \( (-2, 2) \)
- \( B (1, -1) \) translates to \( (-2, 4) \)
- \( C (4, -3) \) translates to \( (1, 2) \)
After this translation, the points will be:
- \( A'' = G (-2, 2) \)
- \( B' = (-2, 4) \)
- \( C' = (1, 2) \)
2. **Rotation**:
Next, we need to perform a rotation or reflection so that the angles and order of the points match. To align \( B' \) and \( E (-2, 5) \), we look at the configuration of the points:
- Notice that \( B' (-2, 4) \) is directly below \( E (-2, 5) \), suggesting a potential rotation around point \( G (-2, 2) \).
To transform \( B' \) to \( E \) and align the remaining points correctly, we can rotate \( 90^\circ \) counter-clockwise around point \( G (-2, 2) \):
- The coordinates will transform as follows:
- Rotating \( A' (-2, 2) \) does not change (it stays \( G \)).
- Rotating \( B' (-2, 4) \) around \( G \) results in \( E (-2, 5) \).
- Rotating \( C' (1, 2) \) around \( G (-2, 2) \) results in the new position that aligns with \( H (-4, 2) \).
With these transformations, we show:
1. **Translation of \( \triangle ABC \)** such that point \( A' \) aligns with point \( G \).
2. **Rotation around \( G \)** to align all corresponding points.
Therefore, \( \triangle ABC \) can be transformed into \( \triangle GHE \) through the described sequence of transformations, proving their congruence.
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