Question

Use the image to answer the question.

An illustration shows a coordinate plane. The x-axis and the y-axis range from negative 6 to 6 in one unit increments. Four points are plotted. The points are connected to form a quadrilateral. Point W is plotted at the coordinates left parenthesis negative 2 comma 1 right parenthesis, Point X is plotted at left parenthesis negative 4 comma negative 3 right parenthesis, point Y is plotted at left parenthesis 5 comma negative 2 right parenthesis, and point Z is plotted at left parenthesis 6 comma 6 right parenthesis. Points W and X, points X and Y, points Y and Z, and points Z and W are connected by line segments to form quadrilateral W X Y Z.

A four-sided figure WXYZ
W
X
Y
Z
is shown on the coordinate plane. The figure is then reflected across the y
y
-axis. Which point of the figure above will end up in Quadrant I?

(1 point)
Responses

Point W
W
Point upper W

Point Y
Y
Point upper Y

Point X
X
Point upper X

Point Z
Z
Point upper Z

Answer 1

To determine which point of the quadrilateral WXYZ will end up in Quadrant I after reflecting across the y-axis, we need to find the new coordinates of each point after the reflection.

The reflection across the y-axis changes the x-coordinate of each point to its opposite sign, while the y-coordinate remains the same.

The points are:
- Point W: (-2, 1) → After reflection: (2, 1)
- Point X: (-4, -3) → After reflection: (4, -3)
- Point Y: (5, -2) → After reflection: (-5, -2)
- Point Z: (6, 6) → After reflection: (-6, 6)

Now, let's determine which of these new points lies in Quadrant I. Quadrant I contains points where both the x and y coordinates are positive.

- Point W: (2, 1) → Quadrant I (both coordinates are positive)
- Point X: (4, -3) → Not in Quadrant I (y-coordinate is negative)
- Point Y: (-5, -2) → Not in Quadrant I (both coordinates are negative)
- Point Z: (-6, 6) → Not in Quadrant I (x-coordinate is negative)

Thus, the point that will end up in Quadrant I after the reflection is **Point W**.