Question
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Force and Work Relationships Quick Check
3 of 43 of 4 Items
Question
A person raises a box with a weight of 50 newtons by 0.5 meter. How much work does the person do in this action?(1 point)
Responses
25 joules
25 joules
0.01 joule
0.01 joule
0.0 joules
0.0 joules
100 joules
Force and Work Relationships Quick Check
3 of 43 of 4 Items
Question
A person raises a box with a weight of 50 newtons by 0.5 meter. How much work does the person do in this action?(1 point)
Responses
25 joules
25 joules
0.01 joule
0.01 joule
0.0 joules
0.0 joules
100 joules
Answers
GPT-4o mini
To calculate the work done by the person in raising the box, you can use the formula for work:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
In this case, since the person is lifting the box vertically, the angle \(\theta\) is 0 degrees (which means \(\cos(0) = 1\)).
Given:
- Force (weight of the box) = 50 newtons
- Distance = 0.5 meters
Now, substituting the values into the formula:
\[ \text{Work} = 50 \, \text{N} \times 0.5 \, \text{m} \times 1 \]
\[ \text{Work} = 50 \, \text{N} \times 0.5 \, \text{m} \]
\[ \text{Work} = 25 \, \text{joules} \]
Therefore, the answer is:
**25 joules**
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
In this case, since the person is lifting the box vertically, the angle \(\theta\) is 0 degrees (which means \(\cos(0) = 1\)).
Given:
- Force (weight of the box) = 50 newtons
- Distance = 0.5 meters
Now, substituting the values into the formula:
\[ \text{Work} = 50 \, \text{N} \times 0.5 \, \text{m} \times 1 \]
\[ \text{Work} = 50 \, \text{N} \times 0.5 \, \text{m} \]
\[ \text{Work} = 25 \, \text{joules} \]
Therefore, the answer is:
**25 joules**