To find out how much wrapping paper Jerry will need, we can calculate the surface area of the box. The formula for the surface area \( A \) of a rectangular box is:
\[ A = 2(lw + lh + wh) \]
where \( l \) is the length, \( w \) is the width, and \( h \) is the height of the box.
Given:
- Length (\( l \)) = 17 cm
- Width (\( w \)) = 10 cm
- Height (\( h \)) = 4 cm
Now, we can plug the dimensions into the formula:
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Calculate \( lw \): \[ lw = 17 \times 10 = 170 , \text{cm}^2 \]
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Calculate \( lh \): \[ lh = 17 \times 4 = 68 , \text{cm}^2 \]
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Calculate \( wh \): \[ wh = 10 \times 4 = 40 , \text{cm}^2 \]
Now sum these values: \[ lw + lh + wh = 170 + 68 + 40 = 278 , \text{cm}^2 \]
Finally, multiply by 2 to get the total surface area: \[ A = 2 \times 278 = 556 , \text{cm}^2 \]
Thus, Jerry will need 556 cm² of wrapping paper to wrap the present.