Question
The illustration displays four distinct circuit configurations.
There are four circuits. Circuit 1 shows a battery and two light bulbs on a parallel circuit. Circuit 2 shows a battery and three light bulbs on series and parallel circuits. Circuit 3 shows a battery and two light bulbs on a series circuit. Circuit 4 shows a battery and three light bulbs on series and parallel circuits.
If one bulb burns out, which circuit will cease to emit light?
(1 point)
Responses
Circuit 3
Circuit 3
Circuit 2
Circuit 2
Circuit 4
Circuit 4
Circuit 1
There are four circuits. Circuit 1 shows a battery and two light bulbs on a parallel circuit. Circuit 2 shows a battery and three light bulbs on series and parallel circuits. Circuit 3 shows a battery and two light bulbs on a series circuit. Circuit 4 shows a battery and three light bulbs on series and parallel circuits.
If one bulb burns out, which circuit will cease to emit light?
(1 point)
Responses
Circuit 3
Circuit 3
Circuit 2
Circuit 2
Circuit 4
Circuit 4
Circuit 1
Answers
GPT-4o mini
To determine which circuit will cease to emit light if one bulb burns out, we need to analyze each circuit configuration.
- **Circuit 1**: This circuit has two light bulbs connected in parallel. If one bulb burns out, the other will still function since they operate independently.
- **Circuit 2**: This circuit has three light bulbs with a combination of series and parallel connections. If one bulb in the series section burns out, it can affect the entire circuit, but if a bulb in the parallel section burns out, the others will still work.
- **Circuit 3**: This circuit has two light bulbs connected in series. If one bulb burns out, the circuit will be broken, and no light will be emitted from either bulb.
- **Circuit 4**: Similar to Circuit 2, this circuit has three light bulbs with series and parallel connections. The same reasoning applies: a burn out in one bulb in series will cease all light, while a burn out in parallel will not affect the others.
Based on this analysis, the correct answer is:
**Circuit 3**
- **Circuit 1**: This circuit has two light bulbs connected in parallel. If one bulb burns out, the other will still function since they operate independently.
- **Circuit 2**: This circuit has three light bulbs with a combination of series and parallel connections. If one bulb in the series section burns out, it can affect the entire circuit, but if a bulb in the parallel section burns out, the others will still work.
- **Circuit 3**: This circuit has two light bulbs connected in series. If one bulb burns out, the circuit will be broken, and no light will be emitted from either bulb.
- **Circuit 4**: Similar to Circuit 2, this circuit has three light bulbs with series and parallel connections. The same reasoning applies: a burn out in one bulb in series will cease all light, while a burn out in parallel will not affect the others.
Based on this analysis, the correct answer is:
**Circuit 3**