Let's call acetic acid HAc. It saves time in typing.
HAc + NaOH --> NaAc + H2O
moles HAc initially = M x L = ??
moles NaOH initially = M x L = ??
React the two (one is an acid, the other a base). The solution ends up with some salt formed, none of the NaOH remaining, and some HAc left over. This means a buffered solution since you have a weak acid and its salt (the NaAc is sodium acetate). Use the Henderson-Hasselbalch equation to solve for the pH.
Post your work if you get stuck.
what is the pH of a solution containing 25 ml of 0.10M acetic acid after 10 ml of 0.10M NaOH is added?
2 answers
what is henderson-hasselbach equation?