Question
How do I calculate the gravitational force between two 50 kg objects separated by 2 meters using the universal gravitation formula?
Answers
GPT-4o mini
To calculate the gravitational force between two objects using Newton's law of universal gravitation, you can use the following formula:
\[
F = G \frac{m_1 m_2}{r^2}
\]
Where:
- \( F \) is the gravitational force between the two masses,
- \( G \) is the gravitational constant, approximately \( 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \),
- \( m_1 \) and \( m_2 \) are the masses of the two objects,
- \( r \) is the distance between the centers of the two masses.
For your case:
- \( m_1 = 50 \, \text{kg} \)
- \( m_2 = 50 \, \text{kg} \)
- \( r = 2 \, \text{m} \)
Now, let's plug in the values into the formula:
\[
F = (6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2) \frac{(50 \, \text{kg})(50 \, \text{kg})}{(2 \, \text{m})^2}
\]
Calculating the terms step-by-step:
1. Calculate the mass product:
\[
50 \, \text{kg} \times 50 \, \text{kg} = 2500 \, \text{kg}^2
\]
2. Calculate the distance squared:
\[
(2 \, \text{m})^2 = 4 \, \text{m}^2
\]
3. Now substitute these values back into the equation:
\[
F = (6.674 \times 10^{-11}) \frac{2500}{4}
\]
4. Simplify the fraction:
\[
\frac{2500}{4} = 625
\]
5. Now calculate the force:
\[
F = (6.674 \times 10^{-11}) \times 625
\]
6. Perform the multiplication:
\[
F = 4.17125 \times 10^{-8} \, \text{N}
\]
Thus, the gravitational force between the two 50 kg objects separated by 2 meters is approximately:
\[
F \approx 4.17 \times 10^{-8} \, \text{N}
\]
\[
F = G \frac{m_1 m_2}{r^2}
\]
Where:
- \( F \) is the gravitational force between the two masses,
- \( G \) is the gravitational constant, approximately \( 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \),
- \( m_1 \) and \( m_2 \) are the masses of the two objects,
- \( r \) is the distance between the centers of the two masses.
For your case:
- \( m_1 = 50 \, \text{kg} \)
- \( m_2 = 50 \, \text{kg} \)
- \( r = 2 \, \text{m} \)
Now, let's plug in the values into the formula:
\[
F = (6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2) \frac{(50 \, \text{kg})(50 \, \text{kg})}{(2 \, \text{m})^2}
\]
Calculating the terms step-by-step:
1. Calculate the mass product:
\[
50 \, \text{kg} \times 50 \, \text{kg} = 2500 \, \text{kg}^2
\]
2. Calculate the distance squared:
\[
(2 \, \text{m})^2 = 4 \, \text{m}^2
\]
3. Now substitute these values back into the equation:
\[
F = (6.674 \times 10^{-11}) \frac{2500}{4}
\]
4. Simplify the fraction:
\[
\frac{2500}{4} = 625
\]
5. Now calculate the force:
\[
F = (6.674 \times 10^{-11}) \times 625
\]
6. Perform the multiplication:
\[
F = 4.17125 \times 10^{-8} \, \text{N}
\]
Thus, the gravitational force between the two 50 kg objects separated by 2 meters is approximately:
\[
F \approx 4.17 \times 10^{-8} \, \text{N}
\]