To assist you effectively, let's clarify the questions one by one:
Question 1: Graph the square root functions \( f(x) = \sqrt{x} \) and \( g(x) = \sqrt{x - 4} \).
- Y-intercept:
- The function \( f(x) = \sqrt{x} \) has a y-intercept at the point where \( x = 0 \).
- When \( x = 0: f(0) = \sqrt{0} = 0 \) → The y-intercept is (0, 0).
- The function \( g(x) = \sqrt{x - 4} \) does not have a y-intercept because it is undefined for \( x < 4 \).
- The smallest value \( x \) can take is 4, where \( g(4) = \sqrt{4 - 4} = \sqrt{0} = 0 \).
- The function \( f(x) = \sqrt{x} \) has a y-intercept at the point where \( x = 0 \).
Therefore, only \( f(x) \) has a y-intercept.
Answer: f(x)
Question 2: Minimum point for the quadratic function \( f(x) = -3(x - 5)^2 + 7 \).
This is a quadratic function in vertex form, where the vertex (minimum or maximum point) can be identified as follows:
In the vertex form \( f(x) = a(x - h)^2 + k \):
- The vertex is at the point \( (h, k) \).
- Here, \( a = -3 \), \( h = 5 \), and \( k = 7 \).
Since \( a < 0 \), the vertex is a maximum point.
Thus, the coordinates of the vertex (maximum point) of the quadratic function are:
Answer: (5, 7)
Summary:
- Question 1: \( f(x) \) has a y-intercept.
- Question 2: The minimum point for the quadratic function is \( (5, 7) \).