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Find the height of a cone that has a volume of 225π 225 𝜋 cubic meters and a diameter of 10 meters.(1 point) The height of the...Question
Find the height of a cone that has a volume of 225π cubic meters and a diameter of 10 meters.(1 point)The height of the cone is meters.
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Answered by
GPT-4o mini
To find the height of the cone, we can use the formula for the volume of a cone:
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
1. **Find the radius**: The diameter of the cone is given as 10 meters, so the radius \( r \) is:
\[
r = \frac{\text{diameter}}{2} = \frac{10}{2} = 5 \text{ meters}
\]
2. **Use the volume formula**: We know the volume \( V \) is \( 225\pi \) cubic meters. Substitute \( V \) and \( r \) into the volume formula:
\[
225\pi = \frac{1}{3} \pi (5^2) h
\]
3. **Simplify**: First, calculate \( 5^2 \):
\[
5^2 = 25
\]
Then substitute it back into the volume equation:
\[
225\pi = \frac{1}{3} \pi (25) h
\]
4. **Cancel \( \pi \)** from both sides:
\[
225 = \frac{1}{3} (25) h
\]
5. **Multiply both sides by 3** to eliminate the fraction:
\[
675 = 25h
\]
6. **Solve for \( h \)**:
\[
h = \frac{675}{25} = 27
\]
Thus, the height of the cone is:
\[
\boxed{27} \text{ meters}
\]
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
1. **Find the radius**: The diameter of the cone is given as 10 meters, so the radius \( r \) is:
\[
r = \frac{\text{diameter}}{2} = \frac{10}{2} = 5 \text{ meters}
\]
2. **Use the volume formula**: We know the volume \( V \) is \( 225\pi \) cubic meters. Substitute \( V \) and \( r \) into the volume formula:
\[
225\pi = \frac{1}{3} \pi (5^2) h
\]
3. **Simplify**: First, calculate \( 5^2 \):
\[
5^2 = 25
\]
Then substitute it back into the volume equation:
\[
225\pi = \frac{1}{3} \pi (25) h
\]
4. **Cancel \( \pi \)** from both sides:
\[
225 = \frac{1}{3} (25) h
\]
5. **Multiply both sides by 3** to eliminate the fraction:
\[
675 = 25h
\]
6. **Solve for \( h \)**:
\[
h = \frac{675}{25} = 27
\]
Thus, the height of the cone is:
\[
\boxed{27} \text{ meters}
\]
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