Question

Factor this trinomial completely
-12x^2 + 45x + 12

Answers

GPT-4o mini
To factor the trinomial \(-12x^2 + 45x + 12\) completely, we can start by finding the greatest common factor (GCF) of the coefficients.

1. The coefficients are \(-12\), \(45\), and \(12\). The GCF is \(3\) (we'll account for the negative later), so we will factor out \(-3\):

\[
-3(4x^2 - 15x - 4)
\]

Now we will focus on factoring the quadratic \(4x^2 - 15x - 4\).

2. We need to find two numbers that multiply to \(4 \cdot (-4) = -16\) (the product of the leading coefficient and the constant term) and add up to \(-15\) (the coefficient of the middle term).

The numbers that work are \(-16\) and \(1\).

3. Now we can rewrite the middle term using these numbers:

\[
4x^2 - 16x + 1x - 4
\]

4. Now group the terms:

\[
(4x^2 - 16x) + (1x - 4)
\]

5. Factor each group:

\[
4x(x - 4) + 1(x - 4)
\]

6. Now, we can factor out the common factor \((x - 4)\):

\[
(4x + 1)(x - 4)
\]

7. Now incorporating the \(-3\) we factored out earlier, we have:

\[
-3(4x + 1)(x - 4)
\]

Thus, the completely factored form of the original trinomial \(-12x^2 + 45x + 12\) is:

\[
-3(4x + 1)(x - 4)
\]