Question
What is the product of the polynomials (x2y+2)(x2−y)
?(1 point)
Responses
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
x3y−x2y2+2x2−2y
?(1 point)
Responses
x4y+x2−2y
x superscript 4 baseline y plus x squared minus 2 y
x4y−xy+x2y
x superscript 4 baseline y minus x y plus x squared y
x4y−x2y2+2x2−2y
x superscript 4 baseline y minus x squared y squared plus 2 x squared minus 2 y
x3y−x2y2+2x2−2y
Answers
GPT-4o mini
To find the product of the polynomials \( (x^2y + 2)(x^2 - y) \), we can use the distributive property (also known as the FOIL method for binomials).
Let's distribute each term in the first polynomial to each term in the second polynomial:
1. Distribute \( x^2y \):
- \( x^2y \cdot x^2 = x^4y \)
- \( x^2y \cdot (-y) = -x^2y^2 \)
2. Distribute \( 2 \):
- \( 2 \cdot x^2 = 2x^2 \)
- \( 2 \cdot (-y) = -2y \)
Now, combining all these results together:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the product of the polynomials is:
\[
\boxed{x^4y - x^2y^2 + 2x^2 - 2y}
\]
This corresponds to the response:
**x4y−x2y2+2x2−2y**
Let's distribute each term in the first polynomial to each term in the second polynomial:
1. Distribute \( x^2y \):
- \( x^2y \cdot x^2 = x^4y \)
- \( x^2y \cdot (-y) = -x^2y^2 \)
2. Distribute \( 2 \):
- \( 2 \cdot x^2 = 2x^2 \)
- \( 2 \cdot (-y) = -2y \)
Now, combining all these results together:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the product of the polynomials is:
\[
\boxed{x^4y - x^2y^2 + 2x^2 - 2y}
\]
This corresponds to the response:
**x4y−x2y2+2x2−2y**