Question

How do I solve the differential equation for a simple harmonic oscillator f(x) = -kx?

Answers

GPT-4o mini
To solve the differential equation for a simple harmonic oscillator, we first need to clarify the equation you're working with. The equation you provided, \( f(x) = -kx \), is actually the force acting on a mass in simple harmonic motion, where \( k \) is the stiffness constant of the spring and \( x \) is the displacement from the equilibrium position.

The dynamics of a simple harmonic oscillator can be described by Newton's second law of motion:

\[
F = ma
\]

Here, the force \( F \) is given by Hooke's law:

\[
F = -kx
\]

Setting these equal, we can express the acceleration \( a \) in terms of displacement \( x \):

\[
ma = -kx
\]

Substituting \( a \) with the second derivative of displacement \( x \):

\[
m \frac{d^2x}{dt^2} = -kx
\]

We can rearrange this equation to obtain the standard form of the simple harmonic oscillator differential equation:

\[
\frac{d^2x}{dt^2} + \frac{k}{m} x = 0
\]

Let \( \omega^2 = \frac{k}{m} \). The equation then simplifies to:

\[
\frac{d^2x}{dt^2} + \omega^2 x = 0
\]

### Solution to the Differential Equation

This is a second-order linear ordinary differential equation with constant coefficients. The general solution can be found by assuming a solution of the form:

\[
x(t) = C_1 \cos(\omega t) + C_2 \sin(\omega t)
\]

where \( C_1 \) and \( C_2 \) are constants determined by initial conditions.

### Determining Constants

To find \( C_1 \) and \( C_2 \), we need initial conditions, such as:

1. The initial displacement \( x(0) = x_0 \)
2. The initial velocity \( \frac{dx}{dt}(0) = v_0 \)

Applying the initial conditions to the general solution:

1. At \( t = 0 \):
\[
x(0) = C_1 \cos(0) + C_2 \sin(0) = C_1 = x_0
\]
So, \( C_1 = x_0 \).

2. The velocity is given by the derivative of \( x(t) \):
\[
\frac{dx}{dt} = -C_1 \omega \sin(\omega t) + C_2 \omega \cos(\omega t)
\]
Evaluating at \( t = 0 \):
\[
\frac{dx}{dt}(0) = -C_1 \omega \sin(0) + C_2 \omega \cos(0) = C_2 \omega = v_0
\]
Thus, \( C_2 = \frac{v_0}{\omega} \).

### Final Solution

Putting it all together, the solution to the differential equation is:

\[
x(t) = x_0 \cos(\omega t) + \frac{v_0}{\omega} \sin(\omega t)
\]

This represents the motion of a simple harmonic oscillator with initial displacement \( x_0 \) and initial velocity \( v_0 \).

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