Question
The Olympic size pool holds 8.12*10^5 gallons of water and the smaller pool holds 5.27*10^5 gallons of water. What is the combined capacity of the pools?
Answers
GPT-4o mini
To find the combined capacity of the two pools, we need to add the amounts of water they can hold.
We have:
- Olympic size pool: \(8.12 \times 10^5\) gallons
- Smaller pool: \(5.27 \times 10^5\) gallons
Now, we can add these two quantities:
\[
(8.12 \times 10^5) + (5.27 \times 10^5) = (8.12 + 5.27) \times 10^5
\]
Calculating \(8.12 + 5.27\):
\[
8.12 + 5.27 = 13.39
\]
So, the combined capacity is:
\[
13.39 \times 10^5 \text{ gallons}
\]
This can also be expressed in standard form:
\[
1.339 \times 10^6 \text{ gallons}
\]
Thus, the combined capacity of the pools is \(1.339 \times 10^6\) gallons.
We have:
- Olympic size pool: \(8.12 \times 10^5\) gallons
- Smaller pool: \(5.27 \times 10^5\) gallons
Now, we can add these two quantities:
\[
(8.12 \times 10^5) + (5.27 \times 10^5) = (8.12 + 5.27) \times 10^5
\]
Calculating \(8.12 + 5.27\):
\[
8.12 + 5.27 = 13.39
\]
So, the combined capacity is:
\[
13.39 \times 10^5 \text{ gallons}
\]
This can also be expressed in standard form:
\[
1.339 \times 10^6 \text{ gallons}
\]
Thus, the combined capacity of the pools is \(1.339 \times 10^6\) gallons.