To determine which circuit will have the greatest electric current, we can use Ohm's Law, which states:
\[ I = \frac{V}{R} \]
where \( I \) is the current in amperes (A), \( V \) is the voltage in volts (V), and \( R \) is the resistance in ohms (Ω).
Let's calculate the electric current for each circuit:
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Circuit 1: \[ I = \frac{20,V}{0.5,Ω} = 40,A \]
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Circuit 2: \[ I = \frac{40,V}{0.5,Ω} = 80,A \]
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Circuit 3: \[ I = \frac{40,V}{0.25,Ω} = 160,A \]
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Circuit 4: \[ I = \frac{60,V}{0.25,Ω} = 240,A \]
Now comparing the calculated currents:
- Circuit 1: 40 A
- Circuit 2: 80 A
- Circuit 3: 160 A
- Circuit 4: 240 A
Conclusion: Circuit 4 has the greatest electric current of 240 A.