Question

f(x)=1/2x+3
with inputs of −4
, −2
, 0, 2, and 4.

Answer 1

To evaluate the function \( f(x) = \frac{1}{2}x + 3 \) using the given inputs \( -4, -2, 0, 2, \) and \( 4 \), we will substitute each of these values into the function.

1. For \( x = -4 \):
\[
f(-4) = \frac{1}{2}(-4) + 3 = -2 + 3 = 1
\]

2. For \( x = -2 \):
\[
f(-2) = \frac{1}{2}(-2) + 3 = -1 + 3 = 2
\]

3. For \( x = 0 \):
\[
f(0) = \frac{1}{2}(0) + 3 = 0 + 3 = 3
\]

4. For \( x = 2 \):
\[
f(2) = \frac{1}{2}(2) + 3 = 1 + 3 = 4
\]

5. For \( x = 4 \):
\[
f(4) = \frac{1}{2}(4) + 3 = 2 + 3 = 5
\]

Now, summarizing the results:

- \( f(-4) = 1 \)
- \( f(-2) = 2 \)
- \( f(0) = 3 \)
- \( f(2) = 4 \)
- \( f(4) = 5 \)

So the outputs for the given inputs are:
- For \( -4 \): \( 1 \)
- For \( -2 \): \( 2 \)
- For \( 0 \): \( 3 \)
- For \( 2 \): \( 4 \)
- For \( 4 \): \( 5 \)