To evaluate the function \( f(x) = \frac{1}{2}x + 3 \) using the given inputs \( -4, -2, 0, 2, \) and \( 4 \), we will substitute each of these values into the function.
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For \( x = -4 \): \[ f(-4) = \frac{1}{2}(-4) + 3 = -2 + 3 = 1 \]
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For \( x = -2 \): \[ f(-2) = \frac{1}{2}(-2) + 3 = -1 + 3 = 2 \]
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For \( x = 0 \): \[ f(0) = \frac{1}{2}(0) + 3 = 0 + 3 = 3 \]
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For \( x = 2 \): \[ f(2) = \frac{1}{2}(2) + 3 = 1 + 3 = 4 \]
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For \( x = 4 \): \[ f(4) = \frac{1}{2}(4) + 3 = 2 + 3 = 5 \]
Now, summarizing the results:
- \( f(-4) = 1 \)
- \( f(-2) = 2 \)
- \( f(0) = 3 \)
- \( f(2) = 4 \)
- \( f(4) = 5 \)
So the outputs for the given inputs are:
- For \( -4 \): \( 1 \)
- For \( -2 \): \( 2 \)
- For \( 0 \): \( 3 \)
- For \( 2 \): \( 4 \)
- For \( 4 \): \( 5 \)