At a pizza eating competition, Davonne at two more than twice as many slices as the runner-up. If Davonne at 11 slices, then how many slices did the runner-up eat?

Answer 1

Let \( x \) be the number of slices the runner-up ate. According to the problem, Davonne ate two more than twice the number of slices the runner-up ate. We can express this relationship with the equation:

\[ D = 2x + 2 \]

Given that Davonne ate 11 slices, we can set up the equation:

\[ 11 = 2x + 2 \]

To solve for \( x \), first, subtract 2 from both sides:

\[ 11 - 2 = 2x \]

This simplifies to:

\[ 9 = 2x \]

Now, divide both sides by 2:

\[ x = \frac{9}{2} = 4.5 \]

Thus, the runner-up ate \( 4.5 \) slices.