Asked by barb
Can someone please help me with these problems?Out of 35 problems these are the ones I can not figure out.Please show all of the stepswith no shortcuts. I am sincerely trying to learn this stuff.Thanks
4y-2+y+36=7y+40-5y
5.3x-5.36=4.24-6.7x
6(x+4)=8(x-2)
In a triangle ABC, angle B is 3 times angle A and angle C is 19 degrees less than 6 times A. What is the size of angle A?
4y-2+y+36=7y+40-5y
5.3x-5.36=4.24-6.7x
6(x+4)=8(x-2)
In a triangle ABC, angle B is 3 times angle A and angle C is 19 degrees less than 6 times A. What is the size of angle A?
Answers
Answered by
Ms. Sue
Here's the first one.
4y-2+y+36=7y+40-5y
4y + y -7y + 5y = 2 - 36 + 40
3y = 6
y = 2
Follow the above procedure and try the others. I'll be glad to check your answers.
4y-2+y+36=7y+40-5y
4y + y -7y + 5y = 2 - 36 + 40
3y = 6
y = 2
Follow the above procedure and try the others. I'll be glad to check your answers.
Answered by
barb
5.3x-5.36=4.24-6.7x
5.3x+6.7x=4.24+5.36
12x=9.6
12x/12=9.6/12
x=.8 If this is wrong can you illustrate what corrections need to be made?
6(x+4)=8(x-2)
6x+24=8x-16
14x=24+16
14x=40
14x/14=40/14
x=2.8571428
that does not even sound right
In a triangle ABC, angle B is 3 times angle A and angle C is 19 degrees less than 6 times A. What is the size of angle A?
(3A)+(^A-19)+A=180 degrees
10A-19=180
10A-19+19=180+19
10A=199
10A/10=199/10
A=19.9 degrees.
I wouldappreciate any advice you can give me to understand this math. I am about to lose it. Thank you so much.
5.3x+6.7x=4.24+5.36
12x=9.6
12x/12=9.6/12
x=.8 If this is wrong can you illustrate what corrections need to be made?
6(x+4)=8(x-2)
6x+24=8x-16
14x=24+16
14x=40
14x/14=40/14
x=2.8571428
that does not even sound right
In a triangle ABC, angle B is 3 times angle A and angle C is 19 degrees less than 6 times A. What is the size of angle A?
(3A)+(^A-19)+A=180 degrees
10A-19=180
10A-19+19=180+19
10A=199
10A/10=199/10
A=19.9 degrees.
I wouldappreciate any advice you can give me to understand this math. I am about to lose it. Thank you so much.
Answered by
Ms. Sue
The first one is correct.
However, you forgot to subtract in the second problem.
6(x+4)=8(x-2)
6x+24=8x-16
6x - 8x = -24 + (-16)
Your third answer is correct.
However, you forgot to subtract in the second problem.
6(x+4)=8(x-2)
6x+24=8x-16
6x - 8x = -24 + (-16)
Your third answer is correct.
Answered by
barb
Is 20 the correct answer to the problem?
6(x+4)=8(x-2)
I just checked and if I checked right,20 is the answer.What is the rule for getting like variables together. Do you always subtract the right from the left?
6(x+4)=8(x-2)
I just checked and if I checked right,20 is the answer.What is the rule for getting like variables together. Do you always subtract the right from the left?
Answered by
Ms. Sue
Yes. 20 is correct.
Not necessarily. You want to get the unknowns on one side and the knowns on the other side.
Examples:
2x + 5 = 11
2x + 5 - 5 = 11 - 5
11 = 2x + 5
11 - 5 = 2x + 5 - 5
Not necessarily. You want to get the unknowns on one side and the knowns on the other side.
Examples:
2x + 5 = 11
2x + 5 - 5 = 11 - 5
11 = 2x + 5
11 - 5 = 2x + 5 - 5
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