Use the image to answer the question.

An illustration shows a horizontal rectangle of unknown height (in meters) with a circle of diameter 12 meters attached to its top left and a circle of diameter 12 meters attached to its bottom right.

If the surface area of the net diagram of the right circular cylinder is 715.92 meters2
, find the height. Use 3.14 for π
.

(1 point)
Responses

16 meters
16 meters

6.5 meters
6.5 meters

13 meters
13 meters

42 meters

1 answer

To find the height of the right circular cylinder, let's first determine the dimensions involved.

  1. Diameter of the circles: Given that the diameter of each circle is 12 meters, the radius (r) will be: \[ r = \frac{12}{2} = 6 \text{ meters} \]

  2. Surface Area of a Cylinder: The surface area (SA) of a right circular cylinder is given by the formula: \[ SA = 2\pi r(h + r) \] where \( h \) is the height of the cylinder.

  3. Given Surface Area: We know that the surface area is 715.92 square meters. Using \( \pi \approx 3.14 \), we can plug in the values into the formula: \[ 715.92 = 2 \times 3.14 \times 6 (h + 6) \] Simplifying the equation: \[ 715.92 = 2 \times 3.14 \times 6 \times (h + 6) \] \[ 715.92 = 37.68 (h + 6) \]

  4. Solving for \( h + 6 \): \[ h + 6 = \frac{715.92}{37.68} \approx 19 \]

  5. Finding \( h \): \[ h = 19 - 6 = 13 \text{ meters} \]

Therefore, the height of the cylinder is 13 meters.

The correct response is: 13 meters.