Question
Use the table of molar masses to complete the question. Do NOT use any other values except the ones provided in the table below.
Element Molar Mass (g/mol)
carbon 12.01
hydrogen 1.01
oxygen 16.00
A chemist will use a sample of 30g of glucose (C6H12O6
) in an experiment. Determine the number of moles of glucose the chemist will use based on the molar mass values provided in the table. (Your value should be rounded to 2 decimal places; i.e. the hundredths place).
(2 points)
The number of moles the chemist will use is:
moles.
Element Molar Mass (g/mol)
carbon 12.01
hydrogen 1.01
oxygen 16.00
A chemist will use a sample of 30g of glucose (C6H12O6
) in an experiment. Determine the number of moles of glucose the chemist will use based on the molar mass values provided in the table. (Your value should be rounded to 2 decimal places; i.e. the hundredths place).
(2 points)
The number of moles the chemist will use is:
moles.
Answers
GPT-4o mini
To determine the number of moles of glucose (C₆H₁₂O₆) in a 30g sample, we first need to calculate the molar mass of glucose using the given molar masses for carbon, hydrogen, and oxygen.
The molar mass of glucose (C₆H₁₂O₆) can be calculated as follows:
- Carbon: 6 atoms × 12.01 g/mol = 72.06 g/mol
- Hydrogen: 12 atoms × 1.01 g/mol = 12.12 g/mol
- Oxygen: 6 atoms × 16.00 g/mol = 96.00 g/mol
Now, summing these values gives us the total molar mass of glucose:
\[
\text{Molar mass of } C_6H_{12}O_6 = 72.06 \, \text{g/mol} + 12.12 \, \text{g/mol} + 96.00 \, \text{g/mol} = 180.18 \, \text{g/mol}
\]
Next, we can calculate the number of moles using the formula:
\[
\text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]
Substituting in the values:
\[
\text{Number of moles} = \frac{30 \, \text{g}}{180.18 \, \text{g/mol}} \approx 0.1665 \, \text{moles}
\]
Rounding to two decimal places gives:
\[
0.17 \, \text{moles}
\]
Therefore, the number of moles the chemist will use is: **0.17 moles**.
The molar mass of glucose (C₆H₁₂O₆) can be calculated as follows:
- Carbon: 6 atoms × 12.01 g/mol = 72.06 g/mol
- Hydrogen: 12 atoms × 1.01 g/mol = 12.12 g/mol
- Oxygen: 6 atoms × 16.00 g/mol = 96.00 g/mol
Now, summing these values gives us the total molar mass of glucose:
\[
\text{Molar mass of } C_6H_{12}O_6 = 72.06 \, \text{g/mol} + 12.12 \, \text{g/mol} + 96.00 \, \text{g/mol} = 180.18 \, \text{g/mol}
\]
Next, we can calculate the number of moles using the formula:
\[
\text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]
Substituting in the values:
\[
\text{Number of moles} = \frac{30 \, \text{g}}{180.18 \, \text{g/mol}} \approx 0.1665 \, \text{moles}
\]
Rounding to two decimal places gives:
\[
0.17 \, \text{moles}
\]
Therefore, the number of moles the chemist will use is: **0.17 moles**.