To calculate the molar mass of Ethanol (CH3CH2OH), we need to sum the molar masses of all the atoms in the molecular formula.
Ethanol has the following composition:
- 2 carbon (C) atoms
- 6 hydrogen (H) atoms
- 1 oxygen (O) atom
Using the molar masses provided in the table:
- Molar mass of carbon (C) = 12.01 g/mol
- Molar mass of hydrogen (H) = 1.01 g/mol
- Molar mass of oxygen (O) = 16.00 g/mol
Now, we can calculate the total molar mass of Ethanol:
\[ \text{Molar mass of ethanol} = (2 \times \text{molar mass of C}) + (6 \times \text{molar mass of H}) + (1 \times \text{molar mass of O}) \]
Substituting in the values:
\[ = (2 \times 12.01 , \text{g/mol}) + (6 \times 1.01 , \text{g/mol}) + (1 \times 16.00 , \text{g/mol}) \]
Calculating each term:
- \( 2 \times 12.01 = 24.02 , \text{g/mol} \)
- \( 6 \times 1.01 = 6.06 , \text{g/mol} \)
- \( 1 \times 16.00 = 16.00 , \text{g/mol} \)
Now adding these results together:
\[ 24.02 + 6.06 + 16.00 = 46.08 , \text{g/mol} \]
Therefore, the molar mass of Ethanol is:
46.08 grams